Vaidev, Glen and Xavier had some balls. Glen had 80% less balls than Vaidev. Glen had ³₈ of Xavier's. After Vaidev gave 120 balls to Glen, he had ¹₅ of what Glen had. How many more balls did Xavier have than Vaidev in the end?

Vaidev	Glen	Xavier
5x3	1x3
	3x1	8x1
15	3	8

	Xavier	Vaidev	Glen	Total balls of  Vaidev and Glen
Before	8x1 = 8 u	15x1 = 15 u	3x1 = 3 u	18x1 = 18 u
Change		- 120	+ 120
After	8 u	1x3 = 3 u	5x3 = 15 u	6x3 = 18 u

Number of balls that Glen had less than Vaidev at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Vaidev : Glen = 5 : 1

The number of balls that Glen had at first is repeated.  Make the number of balls that Glen had at first the same.  LCM of 1 and 3 is 3.

When Vaidev gave 120 balls to Glen, the total number of balls that Glen and Vaidev had at first and in the end remains the same.  Make the total number of balls that Glen and Vaidev had the same.  LCM of 18 and 6 is 18.

Number of balls that Vaidev gave to Glen
= 15 u - 3 u
= 12 u

12 u = 120

1 u = 120 ÷ 12 = 10

Number of balls that Xavier had more than Vaidev in the end
= 8 u - 3 u
= 5 u
= 5 x 10
= 50

Answer(s): 50