Reggie, Simon and Seth had some marbles. Simon had 40% more marbles than Reggie. Simon had ⁴₇ of Seth's. After Reggie gave 120 marbles to Simon, he had ¹₅ of what Simon had. How many more marbles did Seth have than Simon in the end?

Reggie	Simon	Seth
5x4	7x4
	4x7	7x7
20	28	49

	Seth	Reggie	Simon	Total marbles of  Reggie and Simon
Before	49x1 = 49 u	20x1 = 20 u	28x1 = 28 u	48x1 = 48 u
Change		- 120	+ 120
After	49 u	1x8 = 8 u	5x8 = 40 u	6x8 = 48 u

Number of marbles that Simon had more than Reggie at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Reggie : Simon = 5 : 7

The number of marbles that Simon had at first is repeated.  Make the number of marbles that Simon had at first the same.  LCM of 7 and 4 is 28.

When Reggie gave 120 marbles to Simon, the total number of marbles that Simon and Reggie had at first and in the end remains the same.  Make the total number of marbles that Simon and Reggie had the same.  LCM of 48 and 6 is 48.

Number of marbles that Reggie gave to Simon
= 20 u - 8 u
= 12 u

12 u = 120

1 u = 120 ÷ 12 = 10

Number of marbles that Seth had more than Simon in the end
= 49 u - 40 u
= 9 u
= 9 x 10
= 90

Answer(s): 90