Sean, David and Vaidev had some beads. David had 25% more beads than Sean. David had ²₅ of Vaidev's. After Sean gave 84 beads to David, he had ¹₃ of what David had. How many more beads did Vaidev have than David in the end?

Sean	David	Vaidev
4x2	5x2
	2x5	5x5
8	10	25

	Vaidev	Sean	David	Total beads of  Sean and David
Before	25x2 = 50 u	8x2 = 16 u	10x2 = 20 u	18x2 = 36 u
Change		- 84	+ 84
After	50 u	1x9 = 9 u	3x9 = 27 u	4x9 = 36 u

Number of beads that David had more than Sean at first in percent
= 100%+ 25%
= 125%

125% = ¹²⁵₁₀₀ = ⁵₄

Sean : David = 4 : 5

The number of beads that David had at first is repeated.  Make the number of beads that David had at first the same.  LCM of 5 and 2 is 10.

When Sean gave 84 beads to David, the total number of beads that David and Sean had at first and in the end remains the same.  Make the total number of beads that David and Sean had the same.  LCM of 18 and 4 is 36.

Number of beads that Sean gave to David
= 16 u - 9 u
= 7 u

7 u = 84

1 u = 84 ÷ 7 = 12

Number of beads that Vaidev had more than David in the end
= 50 u - 27 u
= 23 u
= 23 x 12
= 276

Answer(s): 276