Riordan, Albert and Elijah had some marbles. Albert had 20% more marbles than Riordan. Albert had ²₅ of Elijah's. After Riordan gave 36 marbles to Albert, he had ¹₃ of what Albert had. How many more marbles did Elijah have than Albert in the end?

Riordan	Albert	Elijah
5x1	6x1
	2x3	5x3
5	6	15

	Elijah	Riordan	Albert	Total marbles of  Riordan and Albert
Before	15x4 = 60 u	5x4 = 20 u	6x4 = 24 u	11x4 = 44 u
Change		- 36	+ 36
After	60 u	1x11 = 11 u	3x11 = 33 u	4x11 = 44 u

Number of marbles that Albert had more than Riordan at first in percent
= 100%+ 20%
= 120%

120% = ¹²⁰₁₀₀ = ⁶₅

Riordan : Albert = 5 : 6

The number of marbles that Albert had at first is repeated.  Make the number of marbles that Albert had at first the same.  LCM of 6 and 2 is 6.

When Riordan gave 36 marbles to Albert, the total number of marbles that Albert and Riordan had at first and in the end remains the same.  Make the total number of marbles that Albert and Riordan had the same.  LCM of 11 and 4 is 44.

Number of marbles that Riordan gave to Albert
= 20 u - 11 u
= 9 u

9 u = 36

1 u = 36 ÷ 9 = 4

Number of marbles that Elijah had more than Albert in the end
= 60 u - 33 u
= 27 u
= 27 x 4
= 108

Answer(s): 108