Lee, Valen and Nick had some balls. Valen had 40% more balls than Lee. Valen had ³₈ of Nick's. After Lee gave 36 balls to Valen, he had ¹₃ of what Valen had. How many more balls did Nick have than Valen in the end?

Lee	Valen	Nick
5x3	7x3
	3x7	8x7
15	21	56

	Nick	Lee	Valen	Total balls of  Lee and Valen
Before	56x1 = 56 u	15x1 = 15 u	21x1 = 21 u	36x1 = 36 u
Change		- 36	+ 36
After	56 u	1x9 = 9 u	3x9 = 27 u	4x9 = 36 u

Number of balls that Valen had more than Lee at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Lee : Valen = 5 : 7

The number of balls that Valen had at first is repeated.  Make the number of balls that Valen had at first the same.  LCM of 7 and 3 is 21.

When Lee gave 36 balls to Valen, the total number of balls that Valen and Lee had at first and in the end remains the same.  Make the total number of balls that Valen and Lee had the same.  LCM of 36 and 4 is 36.

Number of balls that Lee gave to Valen
= 15 u - 9 u
= 6 u

6 u = 36

1 u = 36 ÷ 6 = 6

Number of balls that Nick had more than Valen in the end
= 56 u - 27 u
= 29 u
= 29 x 6
= 174

Answer(s): 174