Wesley, Caden and Oscar had some balls. Caden had 60% more balls than Wesley. Caden had ⁴₇ of Oscar's. After Wesley gave 4 balls to Caden, he had ¹₂ of what Caden had. How many more balls did Oscar have than Caden in the end?

Wesley	Caden	Oscar
5x1	8x1
	4x2	7x2
5	8	14

	Oscar	Wesley	Caden	Total balls of  Wesley and Caden
Before	14x3 = 42 u	5x3 = 15 u	8x3 = 24 u	13x3 = 39 u
Change		- 4	+ 4
After	42 u	1x13 = 13 u	2x13 = 26 u	3x13 = 39 u

Number of balls that Caden had more than Wesley at first in percent
= 100%+ 60%
= 160%

160% = ¹⁶⁰₁₀₀ = ⁸₅

Wesley : Caden = 5 : 8

The number of balls that Caden had at first is repeated.  Make the number of balls that Caden had at first the same.  LCM of 8 and 4 is 8.

When Wesley gave 4 balls to Caden, the total number of balls that Caden and Wesley had at first and in the end remains the same.  Make the total number of balls that Caden and Wesley had the same.  LCM of 13 and 3 is 39.

Number of balls that Wesley gave to Caden
= 15 u - 13 u
= 2 u

2 u = 4

1 u = 4 ÷ 2 = 2

Number of balls that Oscar had more than Caden in the end
= 42 u - 26 u
= 16 u
= 16 x 2
= 32

Answer(s): 32