Michael, George and Bryan had some marbles. George had 20% less marbles than Michael. George had ⁵₈ of Bryan's. After Michael gave 100 marbles to George, he had ¹₂ of what George had. How many more marbles did Bryan have than Michael in the end?

Michael	George	Bryan
5x5	4x5
	5x4	8x4
25	20	32

	Bryan	Michael	George	Total marbles of  Michael and George
Before	32x1 = 32 u	25x1 = 25 u	20x1 = 20 u	45x1 = 45 u
Change		- 100	+ 100
After	32 u	1x15 = 15 u	2x15 = 30 u	3x15 = 45 u

Number of marbles that George had less than Michael at first in percent
= 100% - 20%
= 80%

80% = ⁸⁰₁₀₀ = ⁴₅

Michael : George = 5 : 4

The number of marbles that George had at first is repeated.  Make the number of marbles that George had at first the same.  LCM of 4 and 5 is 20.

When Michael gave 100 marbles to George, the total number of marbles that George and Michael had at first and in the end remains the same.  Make the total number of marbles that George and Michael had the same.  LCM of 45 and 3 is 45.

Number of marbles that Michael gave to George
= 25 u - 15 u
= 10 u

10 u = 100

1 u = 100 ÷ 10 = 10

Number of marbles that Bryan had more than Michael in the end
= 32 u - 15 u
= 17 u
= 17 x 10
= 170

Answer(s): 170