Eric, Ivan and Justin had some balls. Ivan had 80% less balls than Eric. Ivan had ⁵₈ of Justin's. After Eric gave 95 balls to Ivan, he had ¹₄ of what Ivan had. How many more balls did Justin have than Eric in the end?

Eric	Ivan	Justin
5x5	1x5
	5x1	8x1
25	5	8

	Justin	Eric	Ivan	Total balls of  Eric and Ivan
Before	8x1 = 8 u	25x1 = 25 u	5x1 = 5 u	30x1 = 30 u
Change		- 95	+ 95
After	8 u	1x6 = 6 u	4x6 = 24 u	5x6 = 30 u

Number of balls that Ivan had less than Eric at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Eric : Ivan = 5 : 1

The number of balls that Ivan had at first is repeated.  Make the number of balls that Ivan had at first the same.  LCM of 1 and 5 is 5.

When Eric gave 95 balls to Ivan, the total number of balls that Ivan and Eric had at first and in the end remains the same.  Make the total number of balls that Ivan and Eric had the same.  LCM of 30 and 5 is 30.

Number of balls that Eric gave to Ivan
= 25 u - 6 u
= 19 u

19 u = 95

1 u = 95 ÷ 19 = 5

Number of balls that Justin had more than Eric in the end
= 8 u - 6 u
= 2 u
= 2 x 5
= 10

Answer(s): 10