Owen, Neave and Glen had some balls. Neave had 80% less balls than Owen. Neave had ³₅ of Glen's. After Owen gave 60 balls to Neave, he had ¹₅ of what Neave had. How many more balls did Glen have than Owen in the end?

Owen	Neave	Glen
5x3	1x3
	3x1	5x1
15	3	5

	Glen	Owen	Neave	Total balls of  Owen and Neave
Before	5x1 = 5 u	15x1 = 15 u	3x1 = 3 u	18x1 = 18 u
Change		- 60	+ 60
After	5 u	1x3 = 3 u	5x3 = 15 u	6x3 = 18 u

Number of balls that Neave had less than Owen at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Owen : Neave = 5 : 1

The number of balls that Neave had at first is repeated.  Make the number of balls that Neave had at first the same.  LCM of 1 and 3 is 3.

When Owen gave 60 balls to Neave, the total number of balls that Neave and Owen had at first and in the end remains the same.  Make the total number of balls that Neave and Owen had the same.  LCM of 18 and 6 is 18.

Number of balls that Owen gave to Neave
= 15 u - 3 u
= 12 u

12 u = 60

1 u = 60 ÷ 12 = 5

Number of balls that Glen had more than Owen in the end
= 5 u - 3 u
= 2 u
= 2 x 5
= 10

Answer(s): 10