Charlie, Sean and Flynn had some beads. Sean had 40% less beads than Charlie. Sean had ²₇ of Flynn's. After Charlie gave 126 beads to Sean, he had ¹₂ of what Sean had. How many more beads did Flynn have than Charlie in the end?

Charlie	Sean	Flynn
5x2	3x2
	2x3	7x3
10	6	21

	Flynn	Charlie	Sean	Total beads of  Charlie and Sean
Before	21x3 = 63 u	10x3 = 30 u	6x3 = 18 u	16x3 = 48 u
Change		- 126	+ 126
After	63 u	1x16 = 16 u	2x16 = 32 u	3x16 = 48 u

Number of beads that Sean had less than Charlie at first in percent
= 100% - 40%
= 60%

60% = ⁶⁰₁₀₀ = ³₅

Charlie : Sean = 5 : 3

The number of beads that Sean had at first is repeated.  Make the number of beads that Sean had at first the same.  LCM of 3 and 2 is 6.

When Charlie gave 126 beads to Sean, the total number of beads that Sean and Charlie had at first and in the end remains the same.  Make the total number of beads that Sean and Charlie had the same.  LCM of 16 and 3 is 48.

Number of beads that Charlie gave to Sean
= 30 u - 16 u
= 14 u

14 u = 126

1 u = 126 ÷ 14 = 9

Number of beads that Flynn had more than Charlie in the end
= 63 u - 16 u
= 47 u
= 47 x 9
= 423

Answer(s): 423