Oscar, Zeph and Lee had some marbles. Zeph had 80% less marbles than Oscar. Zeph had ³₈ of Lee's. After Oscar gave 168 marbles to Zeph, he had ¹₃ of what Zeph had. How many more marbles did Lee have than Oscar in the end?

Oscar	Zeph	Lee
5x3	1x3
	3x1	8x1
15	3	8

	Lee	Oscar	Zeph	Total marbles of  Oscar and Zeph
Before	8x2 = 16 u	15x2 = 30 u	3x2 = 6 u	18x2 = 36 u
Change		- 168	+ 168
After	16 u	1x9 = 9 u	3x9 = 27 u	4x9 = 36 u

Number of marbles that Zeph had less than Oscar at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Oscar : Zeph = 5 : 1

The number of marbles that Zeph had at first is repeated.  Make the number of marbles that Zeph had at first the same.  LCM of 1 and 3 is 3.

When Oscar gave 168 marbles to Zeph, the total number of marbles that Zeph and Oscar had at first and in the end remains the same.  Make the total number of marbles that Zeph and Oscar had the same.  LCM of 18 and 4 is 36.

Number of marbles that Oscar gave to Zeph
= 30 u - 9 u
= 21 u

21 u = 168

1 u = 168 ÷ 21 = 8

Number of marbles that Lee had more than Oscar in the end
= 16 u - 9 u
= 7 u
= 7 x 8
= 56

Answer(s): 56