Harry, Ian and Pierre had some marbles. Ian had 25% more marbles than Harry. Ian had ²₅ of Pierre's. After Harry gave 14 marbles to Ian, he had ¹₂ of what Ian had. How many more marbles did Pierre have than Ian in the end?

Harry	Ian	Pierre
4x2	5x2
	2x5	5x5
8	10	25

	Pierre	Harry	Ian	Total marbles of  Harry and Ian
Before	25x1 = 25 u	8x1 = 8 u	10x1 = 10 u	18x1 = 18 u
Change		- 14	+ 14
After	25 u	1x6 = 6 u	2x6 = 12 u	3x6 = 18 u

Number of marbles that Ian had more than Harry at first in percent
= 100%+ 25%
= 125%

125% = ¹²⁵₁₀₀ = ⁵₄

Harry : Ian = 4 : 5

The number of marbles that Ian had at first is repeated.  Make the number of marbles that Ian had at first the same.  LCM of 5 and 2 is 10.

When Harry gave 14 marbles to Ian, the total number of marbles that Ian and Harry had at first and in the end remains the same.  Make the total number of marbles that Ian and Harry had the same.  LCM of 18 and 3 is 18.

Number of marbles that Harry gave to Ian
= 8 u - 6 u
= 2 u

2 u = 14

1 u = 14 ÷ 2 = 7

Number of marbles that Pierre had more than Ian in the end
= 25 u - 12 u
= 13 u
= 13 x 7
= 91

Answer(s): 91