Wesley, Japheth and Luis had some marbles. Japheth had 80% less marbles than Wesley. Japheth had
47 of Luis's. After Wesley gave 80 marbles to Japheth, he had
15 of what Japheth had. How many more marbles did Luis have than Wesley in the end?
Wesley |
Japheth |
Luis |
5x4 |
1x4 |
|
|
4x1 |
7x1 |
20 |
4 |
7 |
|
Luis |
Wesley |
Japheth |
Total marbles of Wesley and Japheth |
Before |
7x1 = 7 u |
20x1 = 20 u |
4x1 = 4 u |
24x1 = 24 u |
Change |
|
- 80 |
+ 80 |
|
After |
7 u |
1x4 = 4 u |
5x4 = 20 u |
6x4 = 24 u |
Number of marbles that Japheth had less than Wesley at first in percent
= 100% - 80%
= 20%
20% =
20100 =
15 Wesley : Japheth = 5 : 1
The number of marbles that Japheth had at first is repeated. Make the number of marbles that Japheth had at first the same. LCM of 1 and 4 is 4.
When Wesley gave 80 marbles to Japheth, the total number of marbles that Japheth and Wesley had at first and in the end remains the same. Make the total number of marbles that Japheth and Wesley had the same. LCM of 24 and 6 is 24.
Number of marbles that Wesley gave to Japheth
= 20 u - 4 u
= 16 u
16 u = 80
1 u = 80 ÷ 16 = 5
Number of marbles that Luis had more than Wesley in the end
= 7 u - 4 u
= 3 u
= 3 x 5
= 15
Answer(s): 15