Elijah, Albert and Vincent had some beads. Albert had 25% more beads than Elijah. Albert had
38 of Vincent's. After Elijah gave 12 beads to Albert, he had
12 of what Albert had. How many more beads did Vincent have than Albert in the end?
Elijah |
Albert |
Vincent |
4x3 |
5x3 |
|
|
3x5 |
8x5 |
12 |
15 |
40 |
|
Vincent |
Elijah |
Albert |
Total beads of Elijah and Albert |
Before |
40x1 = 40 u |
12x1 = 12 u |
15x1 = 15 u |
27x1 = 27 u |
Change |
|
- 12 |
+ 12 |
|
After |
40 u |
1x9 = 9 u |
2x9 = 18 u |
3x9 = 27 u |
Number of beads that Albert had more than Elijah at first in percent
= 100%+ 25%
= 125%
125% =
125100 =
54 Elijah : Albert = 4 : 5
The number of beads that Albert had at first is repeated. Make the number of beads that Albert had at first the same. LCM of 5 and 3 is 15.
When Elijah gave 12 beads to Albert, the total number of beads that Albert and Elijah had at first and in the end remains the same. Make the total number of beads that Albert and Elijah had the same. LCM of 27 and 3 is 27.
Number of beads that Elijah gave to Albert
= 12 u - 9 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of beads that Vincent had more than Albert in the end
= 40 u - 18 u
= 22 u
= 22 x 4
= 88
Answer(s): 88