Daniel, Zane and Simon had some marbles. Zane had 40% less marbles than Daniel. Zane had ²₇ of Simon's. After Daniel gave 28 marbles to Zane, he had ¹₂ of what Zane had. How many more marbles did Simon have than Daniel in the end?

Daniel	Zane	Simon
5x2	3x2
	2x3	7x3
10	6	21

	Simon	Daniel	Zane	Total marbles of  Daniel and Zane
Before	21x3 = 63 u	10x3 = 30 u	6x3 = 18 u	16x3 = 48 u
Change		- 28	+ 28
After	63 u	1x16 = 16 u	2x16 = 32 u	3x16 = 48 u

Number of marbles that Zane had less than Daniel at first in percent
= 100% - 40%
= 60%

60% = ⁶⁰₁₀₀ = ³₅

Daniel : Zane = 5 : 3

The number of marbles that Zane had at first is repeated.  Make the number of marbles that Zane had at first the same.  LCM of 3 and 2 is 6.

When Daniel gave 28 marbles to Zane, the total number of marbles that Zane and Daniel had at first and in the end remains the same.  Make the total number of marbles that Zane and Daniel had the same.  LCM of 16 and 3 is 48.

Number of marbles that Daniel gave to Zane
= 30 u - 16 u
= 14 u

14 u = 28

1 u = 28 ÷ 14 = 2

Number of marbles that Simon had more than Daniel in the end
= 63 u - 16 u
= 47 u
= 47 x 2
= 94

Answer(s): 94