David, Owen and Flynn had some beads. Owen had 80% more beads than David. Owen had ³₇ of Flynn's. After David gave 18 beads to Owen, he had ¹₃ of what Owen had. How many more beads did Flynn have than Owen in the end?

David	Owen	Flynn
5x1	9x1
	3x3	7x3
5	9	21

	Flynn	David	Owen	Total beads of  David and Owen
Before	21x2 = 42 u	5x2 = 10 u	9x2 = 18 u	14x2 = 28 u
Change		- 18	+ 18
After	42 u	1x7 = 7 u	3x7 = 21 u	4x7 = 28 u

Number of beads that Owen had more than David at first in percent
= 100%+ 80%
= 180%

180% = ¹⁸⁰₁₀₀ = ⁹₅

David : Owen = 5 : 9

The number of beads that Owen had at first is repeated.  Make the number of beads that Owen had at first the same.  LCM of 9 and 3 is 9.

When David gave 18 beads to Owen, the total number of beads that Owen and David had at first and in the end remains the same.  Make the total number of beads that Owen and David had the same.  LCM of 14 and 4 is 28.

Number of beads that David gave to Owen
= 10 u - 7 u
= 3 u

3 u = 18

1 u = 18 ÷ 3 = 6

Number of beads that Flynn had more than Owen in the end
= 42 u - 21 u
= 21 u
= 21 x 6
= 126

Answer(s): 126