Seth, Brandon and Neave had some beads. Brandon had 20% less beads than Seth. Brandon had ³₅ of Neave's. After Seth gave 36 beads to Brandon, he had ¹₂ of what Brandon had. How many more beads did Neave have than Seth in the end?

Seth	Brandon	Neave
5x3	4x3
	3x4	5x4
15	12	20

	Neave	Seth	Brandon	Total beads of  Seth and Brandon
Before	20x1 = 20 u	15x1 = 15 u	12x1 = 12 u	27x1 = 27 u
Change		- 36	+ 36
After	20 u	1x9 = 9 u	2x9 = 18 u	3x9 = 27 u

Number of beads that Brandon had less than Seth at first in percent
= 100% - 20%
= 80%

80% = ⁸⁰₁₀₀ = ⁴₅

Seth : Brandon = 5 : 4

The number of beads that Brandon had at first is repeated.  Make the number of beads that Brandon had at first the same.  LCM of 4 and 3 is 12.

When Seth gave 36 beads to Brandon, the total number of beads that Brandon and Seth had at first and in the end remains the same.  Make the total number of beads that Brandon and Seth had the same.  LCM of 27 and 3 is 27.

Number of beads that Seth gave to Brandon
= 15 u - 9 u
= 6 u

6 u = 36

1 u = 36 ÷ 6 = 6

Number of beads that Neave had more than Seth in the end
= 20 u - 9 u
= 11 u
= 11 x 6
= 66

Answer(s): 66