Liam, Vaidev and Peter had some balls. Vaidev had 40% less balls than Liam. Vaidev had ⁵₈ of Peter's. After Liam gave 102 balls to Vaidev, he had ¹₄ of what Vaidev had. How many more balls did Peter have than Liam in the end?

Liam	Vaidev	Peter
5x5	3x5
	5x3	8x3
25	15	24

	Peter	Liam	Vaidev	Total balls of  Liam and Vaidev
Before	24x1 = 24 u	25x1 = 25 u	15x1 = 15 u	40x1 = 40 u
Change		- 102	+ 102
After	24 u	1x8 = 8 u	4x8 = 32 u	5x8 = 40 u

Number of balls that Vaidev had less than Liam at first in percent
= 100% - 40%
= 60%

60% = ⁶⁰₁₀₀ = ³₅

Liam : Vaidev = 5 : 3

The number of balls that Vaidev had at first is repeated.  Make the number of balls that Vaidev had at first the same.  LCM of 3 and 5 is 15.

When Liam gave 102 balls to Vaidev, the total number of balls that Vaidev and Liam had at first and in the end remains the same.  Make the total number of balls that Vaidev and Liam had the same.  LCM of 40 and 5 is 40.

Number of balls that Liam gave to Vaidev
= 25 u - 8 u
= 17 u

17 u = 102

1 u = 102 ÷ 17 = 6

Number of balls that Peter had more than Liam in the end
= 24 u - 8 u
= 16 u
= 16 x 6
= 96

Answer(s): 96