Vincent, Seth and Ken had some beads. Seth had 20% less beads than Vincent. Seth had ²₇ of Ken's. After Vincent gave 28 beads to Seth, he had ¹₅ of what Seth had. How many more beads did Ken have than Vincent in the end?

Vincent	Seth	Ken
5x1	4x1
	2x2	7x2
5	4	14

	Ken	Vincent	Seth	Total beads of  Vincent and Seth
Before	14x2 = 28 u	5x2 = 10 u	4x2 = 8 u	9x2 = 18 u
Change		- 28	+ 28
After	28 u	1x3 = 3 u	5x3 = 15 u	6x3 = 18 u

Number of beads that Seth had less than Vincent at first in percent
= 100% - 20%
= 80%

80% = ⁸⁰₁₀₀ = ⁴₅

Vincent : Seth = 5 : 4

The number of beads that Seth had at first is repeated.  Make the number of beads that Seth had at first the same.  LCM of 4 and 2 is 4.

When Vincent gave 28 beads to Seth, the total number of beads that Seth and Vincent had at first and in the end remains the same.  Make the total number of beads that Seth and Vincent had the same.  LCM of 9 and 6 is 18.

Number of beads that Vincent gave to Seth
= 10 u - 3 u
= 7 u

7 u = 28

1 u = 28 ÷ 7 = 4

Number of beads that Ken had more than Vincent in the end
= 28 u - 3 u
= 25 u
= 25 x 4
= 100

Answer(s): 100