George, David and Luis had some balls. David had 20% more balls than George. David had ³₇ of Luis's. After George gave 48 balls to David, he had ¹₂ of what David had. How many more balls did Luis have than David in the end?

George	David	Luis
5x1	6x1
	3x2	7x2
5	6	14

	Luis	George	David	Total balls of  George and David
Before	14x3 = 42 u	5x3 = 15 u	6x3 = 18 u	11x3 = 33 u
Change		- 48	+ 48
After	42 u	1x11 = 11 u	2x11 = 22 u	3x11 = 33 u

Number of balls that David had more than George at first in percent
= 100%+ 20%
= 120%

120% = ¹²⁰₁₀₀ = ⁶₅

George : David = 5 : 6

The number of balls that David had at first is repeated.  Make the number of balls that David had at first the same.  LCM of 6 and 3 is 6.

When George gave 48 balls to David, the total number of balls that David and George had at first and in the end remains the same.  Make the total number of balls that David and George had the same.  LCM of 11 and 3 is 33.

Number of balls that George gave to David
= 15 u - 11 u
= 4 u

4 u = 48

1 u = 48 ÷ 4 = 12

Number of balls that Luis had more than David in the end
= 42 u - 22 u
= 20 u
= 20 x 12
= 240

Answer(s): 240