Bryan, Caden and Fabian had some balls. Caden had 25% more balls than Bryan. Caden had ²₅ of Fabian's. After Bryan gave 60 balls to Caden, he had ¹₅ of what Caden had. How many more balls did Fabian have than Caden in the end?

Bryan	Caden	Fabian
4x2	5x2
	2x5	5x5
8	10	25

	Fabian	Bryan	Caden	Total balls of  Bryan and Caden
Before	25x1 = 25 u	8x1 = 8 u	10x1 = 10 u	18x1 = 18 u
Change		- 60	+ 60
After	25 u	1x3 = 3 u	5x3 = 15 u	6x3 = 18 u

Number of balls that Caden had more than Bryan at first in percent
= 100%+ 25%
= 125%

125% = ¹²⁵₁₀₀ = ⁵₄

Bryan : Caden = 4 : 5

The number of balls that Caden had at first is repeated.  Make the number of balls that Caden had at first the same.  LCM of 5 and 2 is 10.

When Bryan gave 60 balls to Caden, the total number of balls that Caden and Bryan had at first and in the end remains the same.  Make the total number of balls that Caden and Bryan had the same.  LCM of 18 and 6 is 18.

Number of balls that Bryan gave to Caden
= 8 u - 3 u
= 5 u

5 u = 60

1 u = 60 ÷ 5 = 12

Number of balls that Fabian had more than Caden in the end
= 25 u - 15 u
= 10 u
= 10 x 12
= 120

Answer(s): 120