Japheth, Rael and Will had some balls. Rael had 20% more balls than Japheth. Rael had ²₅ of Will's. After Japheth gave 24 balls to Rael, he had ¹₂ of what Rael had. How many more balls did Will have than Rael in the end?

Japheth	Rael	Will
5x1	6x1
	2x3	5x3
5	6	15

	Will	Japheth	Rael	Total balls of  Japheth and Rael
Before	15x3 = 45 u	5x3 = 15 u	6x3 = 18 u	11x3 = 33 u
Change		- 24	+ 24
After	45 u	1x11 = 11 u	2x11 = 22 u	3x11 = 33 u

Number of balls that Rael had more than Japheth at first in percent
= 100%+ 20%
= 120%

120% = ¹²⁰₁₀₀ = ⁶₅

Japheth : Rael = 5 : 6

The number of balls that Rael had at first is repeated.  Make the number of balls that Rael had at first the same.  LCM of 6 and 2 is 6.

When Japheth gave 24 balls to Rael, the total number of balls that Rael and Japheth had at first and in the end remains the same.  Make the total number of balls that Rael and Japheth had the same.  LCM of 11 and 3 is 33.

Number of balls that Japheth gave to Rael
= 15 u - 11 u
= 4 u

4 u = 24

1 u = 24 ÷ 4 = 6

Number of balls that Will had more than Rael in the end
= 45 u - 22 u
= 23 u
= 23 x 6
= 138

Answer(s): 138