Warren, Charlie and Eric had some balls. Charlie had 40% less balls than Warren. Charlie had ²₅ of Eric's. After Warren gave 56 balls to Charlie, he had ¹₂ of what Charlie had. How many more balls did Eric have than Warren in the end?

Warren	Charlie	Eric
5x2	3x2
	2x3	5x3
10	6	15

	Eric	Warren	Charlie	Total balls of  Warren and Charlie
Before	15x3 = 45 u	10x3 = 30 u	6x3 = 18 u	16x3 = 48 u
Change		- 56	+ 56
After	45 u	1x16 = 16 u	2x16 = 32 u	3x16 = 48 u

Number of balls that Charlie had less than Warren at first in percent
= 100% - 40%
= 60%

60% = ⁶⁰₁₀₀ = ³₅

Warren : Charlie = 5 : 3

The number of balls that Charlie had at first is repeated.  Make the number of balls that Charlie had at first the same.  LCM of 3 and 2 is 6.

When Warren gave 56 balls to Charlie, the total number of balls that Charlie and Warren had at first and in the end remains the same.  Make the total number of balls that Charlie and Warren had the same.  LCM of 16 and 3 is 48.

Number of balls that Warren gave to Charlie
= 30 u - 16 u
= 14 u

14 u = 56

1 u = 56 ÷ 14 = 4

Number of balls that Eric had more than Warren in the end
= 45 u - 16 u
= 29 u
= 29 x 4
= 116

Answer(s): 116