Valen, Michael and Eric had some balls. Michael had 20% less balls than Valen. Michael had ²₅ of Eric's. After Valen gave 121 balls to Michael, he had ¹₃ of what Michael had. How many more balls did Eric have than Valen in the end?

Valen	Michael	Eric
5x1	4x1
	2x2	5x2
5	4	10

	Eric	Valen	Michael	Total balls of  Valen and Michael
Before	10x4 = 40 u	5x4 = 20 u	4x4 = 16 u	9x4 = 36 u
Change		- 121	+ 121
After	40 u	1x9 = 9 u	3x9 = 27 u	4x9 = 36 u

Number of balls that Michael had less than Valen at first in percent
= 100% - 20%
= 80%

80% = ⁸⁰₁₀₀ = ⁴₅

Valen : Michael = 5 : 4

The number of balls that Michael had at first is repeated.  Make the number of balls that Michael had at first the same.  LCM of 4 and 2 is 4.

When Valen gave 121 balls to Michael, the total number of balls that Michael and Valen had at first and in the end remains the same.  Make the total number of balls that Michael and Valen had the same.  LCM of 9 and 4 is 36.

Number of balls that Valen gave to Michael
= 20 u - 9 u
= 11 u

11 u = 121

1 u = 121 ÷ 11 = 11

Number of balls that Eric had more than Valen in the end
= 40 u - 9 u
= 31 u
= 31 x 11
= 341

Answer(s): 341