Andy, Vaidev and Brandon had some balls. Vaidev had 40% less balls than Andy. Vaidev had ⁵₈ of Brandon's. After Andy gave 45 balls to Vaidev, he had ¹₃ of what Vaidev had. How many more balls did Brandon have than Andy in the end?

Andy	Vaidev	Brandon
5x5	3x5
	5x3	8x3
25	15	24

	Brandon	Andy	Vaidev	Total balls of  Andy and Vaidev
Before	24x1 = 24 u	25x1 = 25 u	15x1 = 15 u	40x1 = 40 u
Change		- 45	+ 45
After	24 u	1x10 = 10 u	3x10 = 30 u	4x10 = 40 u

Number of balls that Vaidev had less than Andy at first in percent
= 100% - 40%
= 60%

60% = ⁶⁰₁₀₀ = ³₅

Andy : Vaidev = 5 : 3

The number of balls that Vaidev had at first is repeated.  Make the number of balls that Vaidev had at first the same.  LCM of 3 and 5 is 15.

When Andy gave 45 balls to Vaidev, the total number of balls that Vaidev and Andy had at first and in the end remains the same.  Make the total number of balls that Vaidev and Andy had the same.  LCM of 40 and 4 is 40.

Number of balls that Andy gave to Vaidev
= 25 u - 10 u
= 15 u

15 u = 45

1 u = 45 ÷ 15 = 3

Number of balls that Brandon had more than Andy in the end
= 24 u - 10 u
= 14 u
= 14 x 3
= 42

Answer(s): 42