Will, Ivan and Ethan had some beads. Ivan had 80% less beads than Will. Ivan had ⁴₇ of Ethan's. After Will gave 176 beads to Ivan, he had ¹₅ of what Ivan had. How many more beads did Ethan have than Will in the end?

Will	Ivan	Ethan
5x4	1x4
	4x1	7x1
20	4	7

	Ethan	Will	Ivan	Total beads of  Will and Ivan
Before	7x1 = 7 u	20x1 = 20 u	4x1 = 4 u	24x1 = 24 u
Change		- 176	+ 176
After	7 u	1x4 = 4 u	5x4 = 20 u	6x4 = 24 u

Number of beads that Ivan had less than Will at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Will : Ivan = 5 : 1

The number of beads that Ivan had at first is repeated.  Make the number of beads that Ivan had at first the same.  LCM of 1 and 4 is 4.

When Will gave 176 beads to Ivan, the total number of beads that Ivan and Will had at first and in the end remains the same.  Make the total number of beads that Ivan and Will had the same.  LCM of 24 and 6 is 24.

Number of beads that Will gave to Ivan
= 20 u - 4 u
= 16 u

16 u = 176

1 u = 176 ÷ 16 = 11

Number of beads that Ethan had more than Will in the end
= 7 u - 4 u
= 3 u
= 3 x 11
= 33

Answer(s): 33