Albert, David and Caden had some marbles. David had 80% more marbles than Albert. David had ²₇ of Caden's. After Albert gave 24 marbles to David, he had ¹₃ of what David had. How many more marbles did Caden have than David in the end?

Albert	David	Caden
5x2	9x2
	2x9	7x9
10	18	63

	Caden	Albert	David	Total marbles of  Albert and David
Before	63x1 = 63 u	10x1 = 10 u	18x1 = 18 u	28x1 = 28 u
Change		- 24	+ 24
After	63 u	1x7 = 7 u	3x7 = 21 u	4x7 = 28 u

Number of marbles that David had more than Albert at first in percent
= 100%+ 80%
= 180%

180% = ¹⁸⁰₁₀₀ = ⁹₅

Albert : David = 5 : 9

The number of marbles that David had at first is repeated.  Make the number of marbles that David had at first the same.  LCM of 9 and 2 is 18.

When Albert gave 24 marbles to David, the total number of marbles that David and Albert had at first and in the end remains the same.  Make the total number of marbles that David and Albert had the same.  LCM of 28 and 4 is 28.

Number of marbles that Albert gave to David
= 10 u - 7 u
= 3 u

3 u = 24

1 u = 24 ÷ 3 = 8

Number of marbles that Caden had more than David in the end
= 63 u - 21 u
= 42 u
= 42 x 8
= 336

Answer(s): 336