Seth, Vincent and Perry had some marbles. Vincent had 80% less marbles than Seth. Vincent had ²₅ of Perry's. After Seth gave 49 marbles to Vincent, he had ¹₃ of what Vincent had. How many more marbles did Perry have than Seth in the end?

Seth	Vincent	Perry
5x2	1x2
	2x1	5x1
10	2	5

	Perry	Seth	Vincent	Total marbles of  Seth and Vincent
Before	5x1 = 5 u	10x1 = 10 u	2x1 = 2 u	12x1 = 12 u
Change		- 49	+ 49
After	5 u	1x3 = 3 u	3x3 = 9 u	4x3 = 12 u

Number of marbles that Vincent had less than Seth at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Seth : Vincent = 5 : 1

The number of marbles that Vincent had at first is repeated.  Make the number of marbles that Vincent had at first the same.  LCM of 1 and 2 is 2.

When Seth gave 49 marbles to Vincent, the total number of marbles that Vincent and Seth had at first and in the end remains the same.  Make the total number of marbles that Vincent and Seth had the same.  LCM of 12 and 4 is 12.

Number of marbles that Seth gave to Vincent
= 10 u - 3 u
= 7 u

7 u = 49

1 u = 49 ÷ 7 = 7

Number of marbles that Perry had more than Seth in the end
= 5 u - 3 u
= 2 u
= 2 x 7
= 14

Answer(s): 14