George, Tim and Harry had some beads. Tim had 80% less beads than George. Tim had ³₇ of Harry's. After George gave 84 beads to Tim, he had ¹₅ of what Tim had. How many more beads did Harry have than George in the end?

George	Tim	Harry
5x3	1x3
	3x1	7x1
15	3	7

	Harry	George	Tim	Total beads of  George and Tim
Before	7x1 = 7 u	15x1 = 15 u	3x1 = 3 u	18x1 = 18 u
Change		- 84	+ 84
After	7 u	1x3 = 3 u	5x3 = 15 u	6x3 = 18 u

Number of beads that Tim had less than George at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

George : Tim = 5 : 1

The number of beads that Tim had at first is repeated.  Make the number of beads that Tim had at first the same.  LCM of 1 and 3 is 3.

When George gave 84 beads to Tim, the total number of beads that Tim and George had at first and in the end remains the same.  Make the total number of beads that Tim and George had the same.  LCM of 18 and 6 is 18.

Number of beads that George gave to Tim
= 15 u - 3 u
= 12 u

12 u = 84

1 u = 84 ÷ 12 = 7

Number of beads that Harry had more than George in the end
= 7 u - 3 u
= 4 u
= 4 x 7
= 28

Answer(s): 28