Asher, Daniel and Albert had some balls. Daniel had 40% more balls than Asher. Daniel had ²₇ of Albert's. After Asher gave 54 balls to Daniel, he had ¹₅ of what Daniel had. How many more balls did Albert have than Daniel in the end?

Asher	Daniel	Albert
5x2	7x2
	2x7	7x7
10	14	49

	Albert	Asher	Daniel	Total balls of  Asher and Daniel
Before	49x1 = 49 u	10x1 = 10 u	14x1 = 14 u	24x1 = 24 u
Change		- 54	+ 54
After	49 u	1x4 = 4 u	5x4 = 20 u	6x4 = 24 u

Number of balls that Daniel had more than Asher at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Asher : Daniel = 5 : 7

The number of balls that Daniel had at first is repeated.  Make the number of balls that Daniel had at first the same.  LCM of 7 and 2 is 14.

When Asher gave 54 balls to Daniel, the total number of balls that Daniel and Asher had at first and in the end remains the same.  Make the total number of balls that Daniel and Asher had the same.  LCM of 24 and 6 is 24.

Number of balls that Asher gave to Daniel
= 10 u - 4 u
= 6 u

6 u = 54

1 u = 54 ÷ 6 = 9

Number of balls that Albert had more than Daniel in the end
= 49 u - 20 u
= 29 u
= 29 x 9
= 261

Answer(s): 261