Bobby, George and Ben had some marbles. George had 60% less marbles than Bobby. George had ³₈ of Ben's. After Bobby gave 138 marbles to George, he had ¹₅ of what George had. How many more marbles did Ben have than Bobby in the end?

Bobby	George	Ben
5x3	2x3
	3x2	8x2
15	6	16

	Ben	Bobby	George	Total marbles of  Bobby and George
Before	16x2 = 32 u	15x2 = 30 u	6x2 = 12 u	21x2 = 42 u
Change		- 138	+ 138
After	32 u	1x7 = 7 u	5x7 = 35 u	6x7 = 42 u

Number of marbles that George had less than Bobby at first in percent
= 100% - 60%
= 40%

40% = ⁴⁰₁₀₀ = ²₅

Bobby : George = 5 : 2

The number of marbles that George had at first is repeated.  Make the number of marbles that George had at first the same.  LCM of 2 and 3 is 6.

When Bobby gave 138 marbles to George, the total number of marbles that George and Bobby had at first and in the end remains the same.  Make the total number of marbles that George and Bobby had the same.  LCM of 21 and 6 is 42.

Number of marbles that Bobby gave to George
= 30 u - 7 u
= 23 u

23 u = 138

1 u = 138 ÷ 23 = 6

Number of marbles that Ben had more than Bobby in the end
= 32 u - 7 u
= 25 u
= 25 x 6
= 150

Answer(s): 150