Bryan, Julian and Jenson had some balls. Julian had 20% more balls than Bryan. Julian had ²₅ of Jenson's. After Bryan gave 99 balls to Julian, he had ¹₃ of what Julian had. How many more balls did Jenson have than Julian in the end?

Bryan	Julian	Jenson
5x1	6x1
	2x3	5x3
5	6	15

	Jenson	Bryan	Julian	Total balls of  Bryan and Julian
Before	15x4 = 60 u	5x4 = 20 u	6x4 = 24 u	11x4 = 44 u
Change		- 99	+ 99
After	60 u	1x11 = 11 u	3x11 = 33 u	4x11 = 44 u

Number of balls that Julian had more than Bryan at first in percent
= 100%+ 20%
= 120%

120% = ¹²⁰₁₀₀ = ⁶₅

Bryan : Julian = 5 : 6

The number of balls that Julian had at first is repeated.  Make the number of balls that Julian had at first the same.  LCM of 6 and 2 is 6.

When Bryan gave 99 balls to Julian, the total number of balls that Julian and Bryan had at first and in the end remains the same.  Make the total number of balls that Julian and Bryan had the same.  LCM of 11 and 4 is 44.

Number of balls that Bryan gave to Julian
= 20 u - 11 u
= 9 u

9 u = 99

1 u = 99 ÷ 9 = 11

Number of balls that Jenson had more than Julian in the end
= 60 u - 33 u
= 27 u
= 27 x 11
= 297

Answer(s): 297