Brandon, Jack and Luke had some balls. Jack had 20% less balls than Brandon. Jack had ⁵₈ of Luke's. After Brandon gave 64 balls to Jack, he had ¹₄ of what Jack had. How many more balls did Luke have than Brandon in the end?

Brandon	Jack	Luke
5x5	4x5
	5x4	8x4
25	20	32

	Luke	Brandon	Jack	Total balls of  Brandon and Jack
Before	32x1 = 32 u	25x1 = 25 u	20x1 = 20 u	45x1 = 45 u
Change		- 64	+ 64
After	32 u	1x9 = 9 u	4x9 = 36 u	5x9 = 45 u

Number of balls that Jack had less than Brandon at first in percent
= 100% - 20%
= 80%

80% = ⁸⁰₁₀₀ = ⁴₅

Brandon : Jack = 5 : 4

The number of balls that Jack had at first is repeated.  Make the number of balls that Jack had at first the same.  LCM of 4 and 5 is 20.

When Brandon gave 64 balls to Jack, the total number of balls that Jack and Brandon had at first and in the end remains the same.  Make the total number of balls that Jack and Brandon had the same.  LCM of 45 and 5 is 45.

Number of balls that Brandon gave to Jack
= 25 u - 9 u
= 16 u

16 u = 64

1 u = 64 ÷ 16 = 4

Number of balls that Luke had more than Brandon in the end
= 32 u - 9 u
= 23 u
= 23 x 4
= 92

Answer(s): 92