Brandon, Justin and Albert had some marbles. Justin had 60% more marbles than Brandon. Justin had ⁴₇ of Albert's. After Brandon gave 8 marbles to Justin, he had ¹₂ of what Justin had. How many more marbles did Albert have than Justin in the end?

Brandon	Justin	Albert
5x1	8x1
	4x2	7x2
5	8	14

	Albert	Brandon	Justin	Total marbles of  Brandon and Justin
Before	14x3 = 42 u	5x3 = 15 u	8x3 = 24 u	13x3 = 39 u
Change		- 8	+ 8
After	42 u	1x13 = 13 u	2x13 = 26 u	3x13 = 39 u

Number of marbles that Justin had more than Brandon at first in percent
= 100%+ 60%
= 160%

160% = ¹⁶⁰₁₀₀ = ⁸₅

Brandon : Justin = 5 : 8

The number of marbles that Justin had at first is repeated.  Make the number of marbles that Justin had at first the same.  LCM of 8 and 4 is 8.

When Brandon gave 8 marbles to Justin, the total number of marbles that Justin and Brandon had at first and in the end remains the same.  Make the total number of marbles that Justin and Brandon had the same.  LCM of 13 and 3 is 39.

Number of marbles that Brandon gave to Justin
= 15 u - 13 u
= 2 u

2 u = 8

1 u = 8 ÷ 2 = 4

Number of marbles that Albert had more than Justin in the end
= 42 u - 26 u
= 16 u
= 16 x 4
= 64

Answer(s): 64