Ben, Oscar and Ian had some beads. Oscar had 40% more beads than Ben. Oscar had ⁴₇ of Ian's. After Ben gave 16 beads to Oscar, he had ¹₂ of what Oscar had. How many more beads did Ian have than Oscar in the end?

Ben	Oscar	Ian
5x4	7x4
	4x7	7x7
20	28	49

	Ian	Ben	Oscar	Total beads of  Ben and Oscar
Before	49x1 = 49 u	20x1 = 20 u	28x1 = 28 u	48x1 = 48 u
Change		- 16	+ 16
After	49 u	1x16 = 16 u	2x16 = 32 u	3x16 = 48 u

Number of beads that Oscar had more than Ben at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Ben : Oscar = 5 : 7

The number of beads that Oscar had at first is repeated.  Make the number of beads that Oscar had at first the same.  LCM of 7 and 4 is 28.

When Ben gave 16 beads to Oscar, the total number of beads that Oscar and Ben had at first and in the end remains the same.  Make the total number of beads that Oscar and Ben had the same.  LCM of 48 and 3 is 48.

Number of beads that Ben gave to Oscar
= 20 u - 16 u
= 4 u

4 u = 16

1 u = 16 ÷ 4 = 4

Number of beads that Ian had more than Oscar in the end
= 49 u - 32 u
= 17 u
= 17 x 4
= 68

Answer(s): 68