Riordan, Jack and Reggie had some beads. Jack had 80% less beads than Riordan. Jack had ³₇ of Reggie's. After Riordan gave 72 beads to Jack, he had ¹₂ of what Jack had. How many more beads did Reggie have than Riordan in the end?

Riordan	Jack	Reggie
5x3	1x3
	3x1	7x1
15	3	7

	Reggie	Riordan	Jack	Total beads of  Riordan and Jack
Before	7x1 = 7 u	15x1 = 15 u	3x1 = 3 u	18x1 = 18 u
Change		- 72	+ 72
After	7 u	1x6 = 6 u	2x6 = 12 u	3x6 = 18 u

Number of beads that Jack had less than Riordan at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Riordan : Jack = 5 : 1

The number of beads that Jack had at first is repeated.  Make the number of beads that Jack had at first the same.  LCM of 1 and 3 is 3.

When Riordan gave 72 beads to Jack, the total number of beads that Jack and Riordan had at first and in the end remains the same.  Make the total number of beads that Jack and Riordan had the same.  LCM of 18 and 3 is 18.

Number of beads that Riordan gave to Jack
= 15 u - 6 u
= 9 u

9 u = 72

1 u = 72 ÷ 9 = 8

Number of beads that Reggie had more than Riordan in the end
= 7 u - 6 u
= 1 u
= 1 x 8
= 8

Answer(s): 8