Vaidev, Bobby and Archie had some marbles. Bobby had 25% less marbles than Vaidev. Bobby had ⁴₇ of Archie's. After Vaidev gave 72 marbles to Bobby, he had ¹₃ of what Bobby had. How many more marbles did Archie have than Vaidev in the end?

Vaidev	Bobby	Archie
4x4	3x4
	4x3	7x3
16	12	21

	Archie	Vaidev	Bobby	Total marbles of  Vaidev and Bobby
Before	21x1 = 21 u	16x1 = 16 u	12x1 = 12 u	28x1 = 28 u
Change		- 72	+ 72
After	21 u	1x7 = 7 u	3x7 = 21 u	4x7 = 28 u

Number of marbles that Bobby had less than Vaidev at first in percent
= 100% - 25%
= 75%

75% = ⁷⁵₁₀₀ = ³₄

Vaidev : Bobby = 4 : 3

The number of marbles that Bobby had at first is repeated.  Make the number of marbles that Bobby had at first the same.  LCM of 3 and 4 is 12.

When Vaidev gave 72 marbles to Bobby, the total number of marbles that Bobby and Vaidev had at first and in the end remains the same.  Make the total number of marbles that Bobby and Vaidev had the same.  LCM of 28 and 4 is 28.

Number of marbles that Vaidev gave to Bobby
= 16 u - 7 u
= 9 u

9 u = 72

1 u = 72 ÷ 9 = 8

Number of marbles that Archie had more than Vaidev in the end
= 21 u - 7 u
= 14 u
= 14 x 8
= 112

Answer(s): 112