Japheth, Luis and Wesley had some balls. Luis had 80% more balls than Japheth. Luis had ³₈ of Wesley's. After Japheth gave 33 balls to Luis, he had ¹₃ of what Luis had. How many more balls did Wesley have than Luis in the end?

Japheth	Luis	Wesley
5x1	9x1
	3x3	8x3
5	9	24

	Wesley	Japheth	Luis	Total balls of  Japheth and Luis
Before	24x2 = 48 u	5x2 = 10 u	9x2 = 18 u	14x2 = 28 u
Change		- 33	+ 33
After	48 u	1x7 = 7 u	3x7 = 21 u	4x7 = 28 u

Number of balls that Luis had more than Japheth at first in percent
= 100%+ 80%
= 180%

180% = ¹⁸⁰₁₀₀ = ⁹₅

Japheth : Luis = 5 : 9

The number of balls that Luis had at first is repeated.  Make the number of balls that Luis had at first the same.  LCM of 9 and 3 is 9.

When Japheth gave 33 balls to Luis, the total number of balls that Luis and Japheth had at first and in the end remains the same.  Make the total number of balls that Luis and Japheth had the same.  LCM of 14 and 4 is 28.

Number of balls that Japheth gave to Luis
= 10 u - 7 u
= 3 u

3 u = 33

1 u = 33 ÷ 3 = 11

Number of balls that Wesley had more than Luis in the end
= 48 u - 21 u
= 27 u
= 27 x 11
= 297

Answer(s): 297