Glen, Sean and Jenson had some beads. Sean had 40% more beads than Glen. Sean had ²₇ of Jenson's. After Glen gave 36 beads to Sean, he had ¹₃ of what Sean had. How many more beads did Jenson have than Sean in the end?

Glen	Sean	Jenson
5x2	7x2
	2x7	7x7
10	14	49

	Jenson	Glen	Sean	Total beads of  Glen and Sean
Before	49x1 = 49 u	10x1 = 10 u	14x1 = 14 u	24x1 = 24 u
Change		- 36	+ 36
After	49 u	1x6 = 6 u	3x6 = 18 u	4x6 = 24 u

Number of beads that Sean had more than Glen at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Glen : Sean = 5 : 7

The number of beads that Sean had at first is repeated.  Make the number of beads that Sean had at first the same.  LCM of 7 and 2 is 14.

When Glen gave 36 beads to Sean, the total number of beads that Sean and Glen had at first and in the end remains the same.  Make the total number of beads that Sean and Glen had the same.  LCM of 24 and 4 is 24.

Number of beads that Glen gave to Sean
= 10 u - 6 u
= 4 u

4 u = 36

1 u = 36 ÷ 4 = 9

Number of beads that Jenson had more than Sean in the end
= 49 u - 18 u
= 31 u
= 31 x 9
= 279

Answer(s): 279