Kimberly had 315 cards.
37 were brown and the rest were blue and green. The ratio of the number of blue cards to the number of green cards was 1 : 4. Kimberly decided to buy some more brown cards to increase the number of brown cards to half of the total number of cards.
- How many less blue cards than brown cards did he have at first?
- How many more brown cards did he have to buy?
Brown cards |
Blue cards |
Green cards |
Total |
3x5 |
4x5 |
|
|
1x4 |
4x4 |
|
15 u |
4 u |
16 u |
315 |
|
Brown cards |
Blue cards |
Green cards |
Before |
15 u |
4 u |
16 u |
Change |
+ ? |
|
|
After |
20 u |
20 u |
Comparing brown, blue and green cards in the end |
1 |
1 |
(a)
The total number of blue cards and green cards is repeated. Make the total number of blue cards and green cards the same. LCM of 4 and 5 is 20.
Total number of cards at first
= 15 u + 4 u + 16 u
= 35 u
35 u = 315
1 u = 315 ÷ 35 = 9
Number of less blue cards than brown cards at first
= 15 u - 4 u
= 11 u
= 11 x 9
= 99
(b)
Number of more brown cards that Kimberly had to buy
= 20 u - 15 u
= 5 u
= 5 x 9
= 45
Answer(s): (a) 99; (b) 45