Jane had 385 pens.
37 were purple and the rest were yellow and pink. The ratio of the number of yellow pens to the number of pink pens was 1 : 4. Jane decided to buy some more purple pens to increase the number of purple pens to half of the total number of pens.
- How many less yellow pens than purple pens did he have at first?
- How many more purple pens did he have to buy?
Purple pens |
Yellow pens |
Pink pens |
Total |
3x5 |
4x5 |
|
|
1x4 |
4x4 |
|
15 u |
4 u |
16 u |
385 |
|
Purple pens |
Yellow pens |
Pink pens |
Before |
15 u |
4 u |
16 u |
Change |
+ ? |
|
|
After |
20 u |
20 u |
Comparing purple, yellow and pink pens in the end |
1 |
1 |
(a)
The total number of yellow pens and pink pens is repeated. Make the total number of yellow pens and pink pens the same. LCM of 4 and 5 is 20.
Total number of pens at first
= 15 u + 4 u + 16 u
= 35 u
35 u = 385
1 u = 385 ÷ 35 = 11
Number of less yellow pens than purple pens at first
= 15 u - 4 u
= 11 u
= 11 x 11
= 121
(b)
Number of more purple pens that Jane had to buy
= 20 u - 15 u
= 5 u
= 5 x 11
= 55
Answer(s): (a) 121; (b) 55