Jack had 40 buttons.
35 were brown and the rest were black and blue. The ratio of the number of black buttons to the number of blue buttons was 1 : 3. Jack decided to give away some brown buttons to decrease the number of brown buttons to half of the total number of buttons.
- How many more brown buttons than black buttons did he have at first?
- How many brown buttons did he have to give away?
Brown buttons |
Black buttons |
Blue buttons |
Total |
3x2 |
2x2 |
|
|
1x1 |
3x1 |
|
6 u |
1 u |
3 u |
40 |
|
Brown buttons |
Black buttons |
Blue buttons |
Before |
6 u |
1 u |
3 u |
Change |
- ? |
|
|
After |
4 u |
4 u |
Comparing brown, black and blue buttons in the end |
1 |
1 |
(a)
The total number of black buttons and blue buttons is repeated. Make the total number of black buttons and blue buttons the same. LCM of 2 and 4 is 4.
Total number of buttons at first
= 6 u + 1 u + 3 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Number of more brown buttons than black buttons at first
= 6 u - 1 u
= 5 u
= 5 x 4
= 20
(b)
Number of more brown buttons that Jack had to give away
= 6 u - 4 u
= 2 u
= 2 x 4
= 8
Answer(s): (a) 20; (b) 8