Kimberly had 280 coins.
37 were purple and the rest were red and white. The ratio of the number of red coins to the number of white coins was 1 : 4. Kimberly decided to buy some more purple coins to increase the number of purple coins to half of the total number of coins.
- How many less red coins than purple coins did he have at first?
- How many more purple coins did he have to buy?
Purple coins |
Red coins |
White coins |
Total |
3x5 |
4x5 |
|
|
1x4 |
4x4 |
|
15 u |
4 u |
16 u |
280 |
|
Purple coins |
Red coins |
White coins |
Before |
15 u |
4 u |
16 u |
Change |
+ ? |
|
|
After |
20 u |
20 u |
Comparing purple, red and white coins in the end |
1 |
1 |
(a)
The total number of red coins and white coins is repeated. Make the total number of red coins and white coins the same. LCM of 4 and 5 is 20.
Total number of coins at first
= 15 u + 4 u + 16 u
= 35 u
35 u = 280
1 u = 280 ÷ 35 = 8
Number of less red coins than purple coins at first
= 15 u - 4 u
= 11 u
= 11 x 8
= 88
(b)
Number of more purple coins that Kimberly had to buy
= 20 u - 15 u
= 5 u
= 5 x 8
= 40
Answer(s): (a) 88; (b) 40