Paul had 112 pencils.
47 were purple and the rest were grey and green. The ratio of the number of grey pencils to the number of green pencils was 1 : 5. Paul decided to give away some purple pencils to decrease the number of purple pencils to half of the total number of pencils.
- How many more purple pencils than grey pencils did he have at first?
- How many purple pencils did he have to give away?
Purple pencils |
Grey pencils |
Green pencils |
Total |
4x2 |
3x2 |
|
|
1x1 |
5x1 |
|
8 u |
1 u |
5 u |
112 |
|
Purple pencils |
Grey pencils |
Green pencils |
Before |
8 u |
1 u |
5 u |
Change |
- ? |
|
|
After |
6 u |
6 u |
Comparing purple, grey and green pencils in the end |
1 |
1 |
(a)
The total number of grey pencils and green pencils is repeated. Make the total number of grey pencils and green pencils the same. LCM of 3 and 6 is 6.
Total number of pencils at first
= 8 u + 1 u + 5 u
= 14 u
14 u = 112
1 u = 112 ÷ 14 = 8
Number of more purple pencils than grey pencils at first
= 8 u - 1 u
= 7 u
= 7 x 8
= 56
(b)
Number of more purple pencils that Paul had to give away
= 8 u - 6 u
= 2 u
= 2 x 8
= 16
Answer(s): (a) 56; (b) 16