David had 96 coins.
56 were green and the rest were yellow and pink. The ratio of the number of yellow coins to the number of pink coins was 1 : 3. David decided to give away some green coins to decrease the number of green coins to half of the total number of coins.
- How many more green coins than yellow coins did he have at first?
- How many green coins did he have to give away?
Green coins |
Yellow coins |
Pink coins |
Total |
5x4 |
1x4 |
|
|
1x1 |
3x1 |
|
20 u |
1 u |
3 u |
96 |
|
Green coins |
Yellow coins |
Pink coins |
Before |
20 u |
1 u |
3 u |
Change |
- ? |
|
|
After |
4 u |
4 u |
Comparing green, yellow and pink coins in the end |
1 |
1 |
(a)
The total number of yellow coins and pink coins is repeated. Make the total number of yellow coins and pink coins the same. LCM of 1 and 4 is 4.
Total number of coins at first
= 20 u + 1 u + 3 u
= 24 u
24 u = 96
1 u = 96 ÷ 24 = 4
Number of more green coins than yellow coins at first
= 20 u - 1 u
= 19 u
= 19 x 4
= 76
(b)
Number of more green coins that David had to give away
= 20 u - 4 u
= 16 u
= 16 x 4
= 64
Answer(s): (a) 76; (b) 64