Charlie had 100 pens.
45 were gold and the rest were silver and purple. The ratio of the number of silver pens to the number of purple pens was 1 : 3. Charlie decided to give away some gold pens to decrease the number of gold pens to half of the total number of pens.
- How many more gold pens than silver pens did he have at first?
- How many gold pens did he have to give away?
Gold pens |
Silver pens |
Purple pens |
Total |
4x4 |
1x4 |
|
|
1x1 |
3x1 |
|
16 u |
1 u |
3 u |
100 |
|
Gold pens |
Silver pens |
Purple pens |
Before |
16 u |
1 u |
3 u |
Change |
- ? |
|
|
After |
4 u |
4 u |
Comparing gold, silver and purple pens in the end |
1 |
1 |
(a)
The total number of silver pens and purple pens is repeated. Make the total number of silver pens and purple pens the same. LCM of 1 and 4 is 4.
Total number of pens at first
= 16 u + 1 u + 3 u
= 20 u
20 u = 100
1 u = 100 ÷ 20 = 5
Number of more gold pens than silver pens at first
= 16 u - 1 u
= 15 u
= 15 x 5
= 75
(b)
Number of more gold pens that Charlie had to give away
= 16 u - 4 u
= 12 u
= 12 x 5
= 60
Answer(s): (a) 75; (b) 60