Archie had 275 coins.
35 were green and the rest were pink and brown. The ratio of the number of pink coins to the number of brown coins was 1 : 4. Archie decided to give away some green coins to decrease the number of green coins to half of the total number of coins.
- How many more green coins than pink coins did he have at first?
- How many green coins did he have to give away?
Green coins |
Pink coins |
Brown coins |
Total |
3x5 |
2x5 |
|
|
1x2 |
4x2 |
|
15 u |
2 u |
8 u |
275 |
|
Green coins |
Pink coins |
Brown coins |
Before |
15 u |
2 u |
8 u |
Change |
- ? |
|
|
After |
10 u |
10 u |
Comparing green, pink and brown coins in the end |
1 |
1 |
(a)
The total number of pink coins and brown coins is repeated. Make the total number of pink coins and brown coins the same. LCM of 2 and 5 is 10.
Total number of coins at first
= 15 u + 2 u + 8 u
= 25 u
25 u = 275
1 u = 275 ÷ 25 = 11
Number of more green coins than pink coins at first
= 15 u - 2 u
= 13 u
= 13 x 11
= 143
(b)
Number of more green coins that Archie had to give away
= 15 u - 10 u
= 5 u
= 5 x 11
= 55
Answer(s): (a) 143; (b) 55