Jaslyn had 40 pencils.
25 were purple and the rest were brown and pink. The ratio of the number of brown pencils to the number of pink pencils was 1 : 5. Jaslyn decided to buy some more purple pencils to increase the number of purple pencils to half of the total number of pencils.
- How many less brown pencils than purple pencils did he have at first?
- How many more purple pencils did he have to buy?
Purple pencils |
Brown pencils |
Pink pencils |
Total |
2x2 |
3x2 |
|
|
1x1 |
5x1 |
|
4 u |
1 u |
5 u |
40 |
|
Purple pencils |
Brown pencils |
Pink pencils |
Before |
4 u |
1 u |
5 u |
Change |
+ ? |
|
|
After |
6 u |
6 u |
Comparing purple, brown and pink pencils in the end |
1 |
1 |
(a)
The total number of brown pencils and pink pencils is repeated. Make the total number of brown pencils and pink pencils the same. LCM of 3 and 6 is 6.
Total number of pencils at first
= 4 u + 1 u + 5 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Number of less brown pencils than purple pencils at first
= 4 u - 1 u
= 3 u
= 3 x 4
= 12
(b)
Number of more purple pencils that Jaslyn had to buy
= 6 u - 4 u
= 2 u
= 2 x 4
= 8
Answer(s): (a) 12; (b) 8