Kathy had 126 stickers.
37 were yellow and the rest were brown and green. The ratio of the number of brown stickers to the number of green stickers was 1 : 2. Kathy decided to buy some more yellow stickers to increase the number of yellow stickers to half of the total number of stickers.
- How many less brown stickers than yellow stickers did he have at first?
- How many more yellow stickers did he have to buy?
Yellow stickers |
Brown stickers |
Green stickers |
Total |
3x3 |
4x3 |
|
|
1x4 |
2x4 |
|
9 u |
4 u |
8 u |
126 |
|
Yellow stickers |
Brown stickers |
Green stickers |
Before |
9 u |
4 u |
8 u |
Change |
+ ? |
|
|
After |
12 u |
12 u |
Comparing yellow, brown and green stickers in the end |
1 |
1 |
(a)
The total number of brown stickers and green stickers is repeated. Make the total number of brown stickers and green stickers the same. LCM of 4 and 3 is 12.
Total number of stickers at first
= 9 u + 4 u + 8 u
= 21 u
21 u = 126
1 u = 126 ÷ 21 = 6
Number of less brown stickers than yellow stickers at first
= 9 u - 4 u
= 5 u
= 5 x 6
= 30
(b)
Number of more yellow stickers that Kathy had to buy
= 12 u - 9 u
= 3 u
= 3 x 6
= 18
Answer(s): (a) 30; (b) 18