Brandon had 150 stickers.
35 were gold and the rest were purple and blue. The ratio of the number of purple stickers to the number of blue stickers was 1 : 2. Brandon decided to give away some gold stickers to decrease the number of gold stickers to half of the total number of stickers.
- How many more gold stickers than purple stickers did he have at first?
- How many gold stickers did he have to give away?
Gold stickers |
Purple stickers |
Blue stickers |
Total |
3x3 |
2x3 |
|
|
1x2 |
2x2 |
|
9 u |
2 u |
4 u |
150 |
|
Gold stickers |
Purple stickers |
Blue stickers |
Before |
9 u |
2 u |
4 u |
Change |
- ? |
|
|
After |
6 u |
6 u |
Comparing gold, purple and blue stickers in the end |
1 |
1 |
(a)
The total number of purple stickers and blue stickers is repeated. Make the total number of purple stickers and blue stickers the same. LCM of 2 and 3 is 6.
Total number of stickers at first
= 9 u + 2 u + 4 u
= 15 u
15 u = 150
1 u = 150 ÷ 15 = 10
Number of more gold stickers than purple stickers at first
= 9 u - 2 u
= 7 u
= 7 x 10
= 70
(b)
Number of more gold stickers that Brandon had to give away
= 9 u - 6 u
= 3 u
= 3 x 10
= 30
Answer(s): (a) 70; (b) 30